TransactionScope and multi-threading

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It's my third post about TransactionScope. This time I'll write about using it with multi-threading. Let's start with the following code:

using (var t = new TransactionScope())
{
   var t1 = Task.Factory.StartNew(UpdateDatabase);
   var t2 = Task.Factory.StartNew(UpdateDatabase);
   Task.WaitAll(t1, t2);
   t.Complete();
}

private static void UpdateDatabase()
{
   using (var c = new SqlConnection(connectionString))
   {
      c.Open();

      WriteDebugInfo();

      new SqlCommand(updateCommand, c).ExecuteNonQuery();
   }
}

private static void WriteDebugInfo()
{
   Console.WriteLine("Thread= {0}, LocalIdentifier = {1}, DistributedIdentifier = {2}",
      Thread.CurrentThread.ManagedThreadId,
      Transaction.Current?.TransactionInformation.LocalIdentifier,
      Transaction.Current?.TransactionInformation.DistributedIdentifier);
}

It seems simple but it doesn't work. The problem is that a connection that is created in UpdateDatabase method will not participate in any transaction. We can also observe that WriteDebugInfo will write empty transaction identifiers to the console. It happens because in order to read an ambient transaction (the transaction the code is executed in) TransactionScope uses Transaction.Current property which is thread static (i.e. specific for a thread).

To overcome this issue we have two possibilities. The first one is to use DependentTransacion. However, I'll not show how to do it because since .NET 4.5.1 there is a better way - TransactionScopeAsyncFlowOption enum. Let's try.

using (var t = new TransactionScope(TransactionScopeAsyncFlowOption.Enabled))
{
   ...
}

Unfortunately, there is a big chance that this time we will get TransactionException with the message The operation is not valid for the state of the transaction. in the line with ExecuteNonQuery. The simplified stack trace is:

at System.Transactions.TransactionStatePSPEOperation.get_Status(InternalTransaction tx)
at System.Transactions.TransactionInformation.get_Status()
...
at System.Data.SqlClient.SqlCommand.ExecuteNonQuery()
at Sandbox.Program.UpdateDatabase(Object o)

I read a lot about this but nobody was able to explain why it happens. I also looked into the source code of TransactionStatePSPEOperation class. It was instructive because I learned what is PSPE - Promotable Single Phase Enlistment. However, it also didn't give me an exact answer.

So, I played a little bit with the code and I noticed that the problem occurs when:

• One thread tries to run ExecuteNonQuery.
• Another thread waits for the opening of the connection.

However, when both connections were already opened then the exception wasn't thrown.

At this point it is worth reminding one thing - when there are 2 or more connections opened in a transaction scope at the same time then a transaction is promoted to a distributed one. I'm not 100% sure but I think that the problem occurs because it is not allowed to use a connection which participates in a transaction which is in the middle of promotion to the distributed one. So, the solution is to assure that a transaction will be distributed from the beginning. Here is a fixed code with a magic line (I found it here):

using (var t = new TransactionScope())
{
   //The magic line that makes a transaction distributed
   TransactionInterop.GetTransmitterPropagationToken(Transaction.Current);

   var t1 = Task.Factory.StartNew(UpdateDatabase);
   var t2 = Task.Factory.StartNew(UpdateDatabase);
   Task.WaitAll(t1, t2);
   t.Complete();
}

Nonetheless, the more I think about this the more convinced I'm that using TransactionScope with multi-threading is asking for problems.

How not to use TransactionScope. Another WTF!

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This time I will write again about TransactionScope. It is a very useful class and seems to be extremely easy in use. In majority of cases it is true. However, there are also some pitfalls lurking for developers. Especially for these who don't like to waste time for reading MSDN documentation if not really needed i.e. probably vast majority of us ;)

Some time ago, I was analysing more or less the following code:

using(var t = new TransactionScope())
{
   var c = ConnectionProvider.ProvideConnection();
   //Use a connection to update a database
   //...
   t.Complete();
}

ConnectionProvider is a class that hides details of managing connections to a database. There was also a bug in the code responsible for updating a database which caused exceptions. I fixed it and I run tests again. This time an exception was not thrown but something was wrong because a database contained unexpected data. It looked like the transaction was not rollbacked!

Firstly, I though that it is some kind of magic. However, as usual in this kind of cases it wasn't. I digged into ConnectionProvider and I found out that this class was performing some kind of pooling and a connection wasn't opening every time. It was a big problem because connections opened outside a transaction scope do not participate in a transaction. The solution of this problem is to explicitly enlist a connection in an existing transaction scope with the EnlistTransaction method.

It is also worth highlighting that the described problem won't occur if ConnectionProvider doesn't try to implement polling on its own. In general we don't have to do it because .NET do it for us. The problem will also not occur if using statement is used to close a connection returned by a provider.

TransactionScope + Ninject + a small mistake = WTF

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Sometimes one stupid mistake can cost a lot of time. A few days ago my application (AngularJS + ASP.NET Web API) started crashing because of the following error:

MSDTC on server 'XXX' is unavailable

It was strange. I wasn't aware of any distributed transactions in my application. To be honest, I was using TransacionScope but I was sure that there was no reason to promote a lightweight transaction into a distributed one. To make things more strange the error wasn't reported every time. When I tried to update data for the first time everything was ok. However, the second attempt (and every next) was failing.

It took me some time to examine all recent changes but finally I found a problem. It was quite tricky so I decided to write about it. Let's start with the fact that I use Ninject as a dependency injection container. Among others Ninject allow us to control a lifetime of objects (instances). Particularly, in the case of web applications, we can use:

• InRequestScope method - it tells Ninject that one object of a particular type should be created for each individual request.
• InSingletonScope method - it tells Ninject that one object of a particular type should be created for all requests.

For example:

kernel.Bind(x => x
   .FromAssembliesMatching("test.dll")
   .SelectAllClasses().InheritedFrom(typeof(IInterfaace))
   .BindAllInterfaces()
   .Configure(z => z.InSingletonScope()));

The problem was that accidentally I mixed InSingletonScope and InRequestScope. For example, let's assume that each request requires objects of two classes A and B. Objects of type A are within the request scope and objects of type B are within the singleton scope.

Both objects perform updates/inserts/deletes and are used inside TransacionScope. For the first request it is not a problem. Both objects are initialized within the same request and use the same database connection. It means that a lightweight transaction is used.

However, for the second (and every next) request an object of type B is re-used whereas a new object of type A is created. Object of type B was initiated in the previous request and it uses a different connection than the one used by an object of type A. It means that a distributed transaction will be used in this case.

To sum up:

• DI containers give a great power but with the power comes great responsibility.
• Be careful when using objects of a different scope together. Especially when these objects require data access.
• Be careful when using multiple connections inside TransacionScope. In the case of MSSQL 2005 in this situation a distributed transaction will be always used. In the case of MSSQL 2008 or newer it is possible to use more than one connection inside TransacionScope without automatic promotion. However, if and only if these connections are not opened at the same time.
• TransactionScope automatically escalating to MSDTC on some machines? is a great source of knowledge about TransacionScope and about the process of promoting lightweight transactions into distributed ones.

Do you know OUTPUT clause?

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Today, I'll write about using OUTPUT clause together with INSERT statements. It seems to be that it is not a very well known syntax. However, it is especially useful when use Identity columns to generate keys. Let's start with a simple table:

CREATE TABLE dbo.Main
( 
 Id int Identity (1,1) PRIMARY KEY,
 Code varchar(10),
 UpperCode AS Upper(Code)
);

The old fashioned approach to retrieve a value of Identity column for a new row is to use SCOPE_IDENTITY(). For example:

INSERT INTO dbo.Main (Code) VALUES ('aaa');
SELECT SCOPE_IDENTITY();

With OUTPUT clause it will look in the following way:

DECLARE @InsertedIdentity TABLE(Id int);
INSERT INTO dbo.Main (Code) OUTPUT INSERTED.Id INTO @InsertedIdentity VALUES ('aaa')
SELECT TOP(1) * FROM @InsertedIdentity

You can say wait a minute. If I want to use OUTPUT I have to declare a table variable first and then use SELECT. It is more complex than just using SCOPE_IDENTITY().

Well, the first benefit is that with OUTPUT clause we can read values from many columns, including these that are computed (as it was shown above). However, the real power of OUTPUT clause can be observed if we want to insert many rows into a table:

DECLARE @ToBeInserted TABLE(Code varchar(10), Name varchar(100));

INSERT INTO @ToBeInserted
VALUES ('aaa','1111111111'), ('ddd','2222222222'), ('ccc','3333333333');

DECLARE @Inserted TABLE(Id int, Code varchar(10), UpperCode varchar(10));

INSERT INTO dbo.Main (Code)
OUTPUT INSERTED.Id, INSERTED.Code, INSERTED.UpperCode INTO @Inserted
SELECT Code
FROM @ToBeInserted;

SELECT * FROM @Inserted;

Without OUTPUT we would have to write a nasty loop!

Here is one more example. Let's assume that we have an additional table that references dbo.Main.

CREATE TABLE dbo.Child
( 
 MainId int,
 Name varchar(100),
 CONSTRAINT [FK_Child_Main] FOREIGN KEY(MainId)REFERENCES dbo.Main (Id)
);

We want to insert a few rows into dbo.Main and then related rows to dbo.Child. It is quite easy if we use OUTPUT clause.

INSERT INTO dbo.Child (MainId, Name)
SELECT i.Id, tbi.Name
FROM @ToBeInserted tbi
 JOIN @Inserted i ON i.Code = tbi.Code;

Extremely useful thing that you must know!

At the end it is worth mentioning that OUTPUT clause can be also used together with UPDATE, DELETE or MERGE statements.

Oracle VM VirtualBox and Windows 8.1

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In my day to day work I use a 64 bit version of Windows 8.1 Pro N. I needed a virtualization software so I decided to use a free Oracle VM Virtual Box. Everything was ok up to the moment when I wanted to install a x64 version of an operating system on a fresh virtual machine. To my surprise VirtualBox reported the following error:

VT-x/AMD-V hardware acceleration has been enabled, but is not operational. Your 64-bit guest will fail to detect a 64-bit CPU and will not be able to boot.

Please ensure that you have enabled VT-x/AMD-V properly in the BIOS of your host computer.

After some time I noticed that VirtualBox stopped showing 64 bit versions in the Version list. Well, it was actually good because I couldn't use a64 bit virtual machines anyway ;) But, I still didn't know why it happened.

I checked BIOS settings and it seemed ok. I searched Internet for the answer but everyone were recommended to verify BIOS configuration what I've already done. I needed a new VM quickly so at that point I installed a x86 version of Windows.

A few days later my colleague Przemek suggested that the problem may be in the conflict between Hyper-V and VirtualBox and that I should disable Hyper-V. It was strange because I've never installed Hyper-V. However, I checked and I discovered that Hyper-V features were enabled on my computer. It seems to me that they are installed by default with the operating system.



The solution was easy. I pressed Win+S and typed Turn windows feature on or off. Then, I cleared a box next to Hyper-V and restarted computer. After that I was able to install a x64 version of a operating system on a virtual machine.

To sum up, if:

• Your host system is a x64 version of Windows 8.1.
• Virtualization is enabled in BIOS.
• You use VirtualBox.

And you cannot install x64 operating system on a virtual machine then try to disable Hyper-V.